3^3-2*3+u=(3^3-3*8)(2)+u

Solution for 3^3-2*3+u=(3^3-3*8)(2)+u equation:

3^3-2*3+u=(3^3-3*8)(2)+u

We move all terms to the left:

3^3-2*3+u-((3^3-3*8)(2)+u)=0

We add all the numbers together, and all the variables

u-((3^3-3*8)2+u)+21=0


We calculate terms in parentheses: -((3^3-3*8)2+u), so:

(3^3-3*8)2+u

determiningTheFunctionDomain
u+(3^3-3*8)2

We add all the numbers together, and all the variables

u+6

Back to the equation:

-(u+6)


We get rid of parentheses

u-u-6+21=0

We add all the numbers together, and all the variables

15!=0

There is no solution for this equation